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Find the tangent and normal to the curve y=(4-x)(x+2) at the point (2, 8)

-Tangent is a straight line that touches, but does not intersect, the curve at the point (2,8).

We need to find the gradient of the curve at the point (2, 8). To do this, expand the equation, diffe...

SE
Answered by Sam E. Maths tutor
4319 Views

A curve C is defined by the parametric equations x=(4-e^(2-6t))/4 , y=e^(3t)/(3t), t doesnt = 0. Find the exact value of dy/dx at the point on C where t=2/3 .

To solve this we must use the chain rule which is dy/dt * dt/dx. Firstly, we differentiate dy/dt. For this we must use the quotient rule, this gives us dy/dt=(9te^3t - 3e^3t)/9t^2. Now for dx/dt, by subst...

LK
Answered by Lauren K. Maths tutor
5625 Views

Find the roots of the following equation: x^2 + x - 6 = 0

Student should factorise equation to (x-2)(x+3) = 0 This gives roots of 2 and -3

AR
Answered by Adam R. Maths tutor
1783 Views

How do I solve a simultaneous equation like this: 2x-5y=3, 3x+2y=14 ?

Solving a simultaneous equation finds the point(s) where two lines on a graph intercept. Therefore, one way of solving the equations is to plot the two lines onto the same graph and find the coordinates o...

EG
Answered by Ellie G. Maths tutor
8749 Views

Find the integral of tan^2x dx

You can not integrate tan2x but you can integrate sec2x Since sec2x = 1 + tan2x  Then tan2

NP
Answered by Nandini P. Maths tutor
19971 Views

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