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Using the equation of a straight line: y = mx + c (c is the y axis intercept, m is the gradient and y and x are points on the line (x,y))

e.g. if the gradient of the line was 3 and the line passes ...

First we can equate (19x - 2)/((5 - x)(1 + 6x)) to A/(5-x) + B/(1+6x) which means:
(19x - 2)/((5 - x)(1 + 6x)) = A/(5-x) + B/(1+6x). Then we will turn the RHS into a single fraction:

(19x - 2...

The x-intercepts are where the graph crosses the x-axis
To find the x-intercepts of an equation --> substitute in y = 0 and solve for x

The y-intercepts are where the graph crosses the y-a...

y=k/x²

yx²=k  

1*10²=k

k=100

x=1 y=100

x=2 y=25

x=5 y=4

x=10 y=1

You would first multiply the expression by (3-root(5))/(3-root(5) - which equals 1 - to get (6-2root(5))/14 which then equals 3/7 - (1/7)*root(5) and you are done.