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The x-intercepts are where the graph crosses the x-axis To find the x-intercepts of an equation --> substitute in y = 0 and solve for x
The y-intercepts are where the graph crosses the y-a...
y=k/x2
yx2=k
1*102=k
k=100
x=1 y=100
x=2 y=25
x=5 y=4
x=10 y=1
You would first multiply the expression by (3-root(5))/(3-root(5) - which equals 1 - to get (6-2root(5))/14 which then equals 3/7 - (1/7)*root(5) and you are done.
First differentiate y with respect to x, which gives you dy/dx = 8 - 2x^-2. This needs to equal zero so equate to zero. 8-2x^-2 = 0. You can then bring the 2x^-2 to the other side giving 2x^-2=8. Dividing...
dy/dx = 24e6x - sin(x) + 6
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