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x2 -4=0 becomes (x+2)(x-2)=0
Either one of the two brackets has the value of 0.
If the first bracket is zero, then x+2=0, therefore x=-2
If the second bracket is zero, then...
when differentiating, we multiply the power by the coefficient and then take the power away by 1 so : y= 4x^3 + 3x^2 -5x +1 then 4 x 3= 12 and 3-1 = 2 meaning the solution is 12x^2. 2 x 3 = 6 and 2-1 = 1 ...
Taking the log of both sides we get 5x * ln2 = (2x+1) * ln3. Taking everything that contains x to the left side: x * (5ln2 - 2ln3) = ln3. Therefore x=ln3/(5ln2 - 2ln3) ...
divide fraction by 2
3x+2 / x-1 + 3 = 4
multiply by x-1
3x + 2 + 3x - 3 = 4x - 4
6x -1 = 4x -4
2x = -3
x= -3/2
This problem is a graphical representation of finding the solutions to a pair of simultaneous equations.
In this example we will use the curves y=2x2 , and y=x2+1. This is a v...
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