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This problem is a graphical representation of finding the solutions to a pair of simultaneous equations.

In this example we will use the curves y=2x² , and y=x²+1. This is a v...

Quadratic equations can be tricky, to begin with, but once you get the hang of them they can become one of the best maths tools on offer to you. All quadratic equations with real roots can be solved with ...

3x²+5y+5x(dy/dx)-4y(dy/dx)=0

3x²+5y=(5x-4y)dy/dx

dy/dx=(3x²+5y)/(5x-4y)

Using the quotient rule: Let u=x and v=2x+5 then du/dx= 1 and dv/dx=2 Hence dy/dx=[(2x+5)x1- (2x)]/(2x+5)²             =5/(2x+5)²

First, you must find out the total amount to pay back, this amount will be £720 + 15% of £720. To find 15% of £720, we first calculate 720/100 to find 1% and the multiply by 15: 720/100 = 7.2 *15 = 108. N...