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Firstly, as with any question, make sure to check your formula book in order to find any relevant equations. In this case, the one most relevant to us is U_n = U₁ + d(n-1).
From...

To find the derivative of this, we must differentiate each term with respect to x. This implies d/dx(y^3+2xy+x^2-5=0). We can differentiate each term seperately so d/dx(y^3+2xy+x^2-5=0) is equal to d/dx(y...

new amount = old amount * (1 + interest)^(number of times interest has occured)

new amount = 1.50 * (1 + 0.03)^5 = £1.74 (rounded to 2 decimal places)

To differentiate you bring the power down and multiply it by any coefficients (numbers in front of the xs) then subtract one from the power 

So x³ becomes 3x² 

2x^2...

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