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Simplify (4^2)*(2^3)*16
Indice rules are fundamental in answering this question 1) (ab)(ac) = a(b+c) 2) (ab)/(ac) = a(b-c) 3) (ab)c = a
Solve the equation 3x^2/3 + x^1/3 − 2 = 0
Let u = x^1/3
The equation can therefore be written as:
3u^2+u-2=0
This can be factorised to:
(3u-2)(u+1)+0
Therefore: u = 2/3 or u = -1 OR x^1/3 = 2/3 or x^1/3 = -1
