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If given two parametric equations for a curve, how would you work out an equation for the gradient?

Parametric equations will have both the x and the y coordinates expressed in terms of another paramater, usually t. Gradients of curves are expressed in the form of an equation of dy/

Answered by Mollie W. • Maths tutor

3920 Views

Show that Sec2A - Tan2A = (CosA-SinA)/(CosA+SinA)

Sec2A - Tan2A Definition of Sec and Tan = 1/Cos2A - Sin2A/Cos2A Combining Fractions = (1 - Sin2A) / (Cos2A) Apply Double Angle Formula = (1 - 2SinACosA) / (Cos²A - Sin²A) Make use of...

Answered by James C. • Maths tutor

34877 Views

solve the quadratic equation: x^2-4x+3=0

This equation is asking us to find the value(s) of x that when substituted in place of x in the equation x²-4x+3 the computed value should equal 0. There three potential methods of solving this...

Answered by Taylor R. • Maths tutor

6702 Views

Solve the quadratic 3x^2+11x+6=0

In order to solve the quadratic, we need to factorise it. Consider the coefficient on the x^2, its only factors are 1 and 3 so this tells us that in our factorising we will have something that looks like ...

Answered by Natalie F. • Maths tutor

8397 Views

Solve the following simultaneous equations to obtain values for x and y: 2x + y = 7 & 3x - y = 8.

Label your equations 1 and 2 respectively. Make y the subject of equation 2 by taking away 3x from both sides and multiplying both sides by -1, to get y = 3x - 8. Now substitute this into equation 1 (i.e....

Answered by Pratham M. • Maths tutor

3163 Views