Search over 10,000 free study notes

step 1 remember than the a and b terms locate the centre of the circle on the axis so we can substitute in the centre values for a and b. (x-5)^2 + (y-(-3))^2 = k. (x-5)^2 + (y+3)^2 = k.

Step 2. k ...

Solving a pair of simultaneous equations should ALWAYS begin in labelling each equation. I would go about labelling the first equation (1) and the second (2). A quadratic simulataneous equation question i...

(i): 15x^(2)+7 --- in order to arrive at this answer, we can divide the equation into 3 separate parts: 5x^(3) and 7x and 3. For the first part, you would multiply the first number, 5 by the power, in thi...

First we must think about the fraction on the left hand side - we have to multiply everything by x-1 in order to get rid of the fraction. This leaves us with 3x+2+3(x-1)=4(x-1). Then, we must expand the b...

First of all, the best thing to do is to split the question into its different components:

5 x q^2 x p^12 / 10 (q x p^3)^2

Next we want to get rid of the brackets. With indices there are sev...