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Differentiate the curve to get the gradient function: f'(x)= 2x + 5. Solve for x when f'(x) = 0 --> 2x + 5 = 0, 2x = -5, x = -5/2 Substitute into the original equation to find y: (-2.5)^2 + 5 * -2.5 + ...

2X2 = 4

Here, we have to use implicit differentiation, along with the product rule. Remember that the product rule is (vu)' = vu'+uv'. Moving through the equation we have: x^2+2xy+3y^2 = 4 ==> 2x +2y + 2x*(d...

The trick to working out how to do this, is to remember how to add normal fractions! We know 1/8 + 3/8 = 4/8 . The point here is that IF THE DENOMINATORS ARE THE SAME, we can add the numerators. So what a...

Assuming we are given that x = f(t) and y = g(t), we first differentiate x with respect to t to obtain dx/dt. Then, we differentiate y with respect to t to obtain dy/dt. Much like fractions, we can find d...