Search over 10,000 free study notes

Multiply the first term in the first bracket, so that would be x, with the second bracket. step one: x(x-3) is identical to: x^2 - 3x

We can now multiply the second number in the first bracket, whi...

y = 4x^3 - 5/x^2 Easier to differentiate the 2nd term if it isn't written as a fraction so first rewrite y: y = 4x^3 - 5x^(-2) Then differentiate each term by multiplying each term by the current power of...

To write this sum as a single fraction we need to put both of them over a common denominator. Our common denominator will be the simplest thing that has both 3 and 5 as a factor, which is 15 (x-2)/3 + (x+...

Firstly, note the general equation for a quadratic: ax^2+bx+c. We can see that in the above equation, a=1, b=2 and c=-8. When factorising we have to consider the product ac and b. ac=1(-8)=-8 and b=2. Now...

Taking the value at the ordinates f(1) = 13/4, f(2) = 20/4sqrt(2), f(3) = 39/4sqrt(3), f(4) = 9.5 Then the trapezium rule states the integral is approximately 1/2 * [f(1) + 2f(2) + 2f(3) + f(4)], which (u...