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When given an equation in parametric form, how can you figure out dy/dx?

Assuming we are given that x = f(t) and y = g(t), we first differentiate x with respect to t to obtain dx/dt. Then, we differentiate y with respect to t to obtain dy/dt. Much like fractions, we can find d...

DJ
Answered by Dave J. Maths tutor
3494 Views

Expand and simplify the following equation: 6(x-3) - 4(x-5) = 0

Start off by dealing with the brackets by expanding. The brackets around a part of the equation imply that the entire content of the brackets will be affected by the factor outside of the brackets, in thi...

SH
Answered by Sophia H. Maths tutor
11148 Views

How do I know which SUVAT equation to use?

SUVAT equations link the variables S (displacement), U (initial speed), V(final speed), A(accelerations), and T (time), for situations where there is constant acceleration. Each of the 5 SUVAT equations ...

NV
Answered by Nikul V. Maths tutor
20031 Views

Factorise fully 6x^2-14x

Since there is only two terms it is a case of seeing what both terms have in common. Both share a 2 and an x so having this an the coefficient to the bracket gives 2x(x-7)

MO
Answered by Max O. Maths tutor
7411 Views

Given that y=(4x-3)^3 x sin2x find dy/dx

To begin with it is important to identify which method of differentiation is required here, since there are two terms multiplied together you would initially choose the product rule, differentiating (4x-3...

MO
Answered by Max O. Maths tutor
3454 Views

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