Search over 10,000 free study notes

A. t=0 ; x=250,000 B. 2020, so t=3. plug in to equation > x=250,000e^(0.012)3 = 259,163 (people so cannot round up) C. Population to double so 500,000 = 250,000e^(0.012)t -> 1/0.012(ln2) = t t= 57.7...

the first thing we need to do is rearrange the order of our question to ( 4 x 9 ) x (10^-3 x 10^14). now (4 x 9) = 36 (10^-3 x 10^14) = 10^(-3 + 14) = 10^11 so our answer is 36 x 10^11 however this is not...

step 1 remember than the a and b terms locate the centre of the circle on the axis so we can substitute in the centre values for a and b. (x-5)^2 + (y-(-3))^2 = k. (x-5)^2 + (y+3)^2 = k.

Step 2. k ...

Solving a pair of simultaneous equations should ALWAYS begin in labelling each equation. I would go about labelling the first equation (1) and the second (2). A quadratic simulataneous equation question i...

(i): 15x^(2)+7 --- in order to arrive at this answer, we can divide the equation into 3 separate parts: 5x^(3) and 7x and 3. For the first part, you would multiply the first number, 5 by the power, in thi...