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y = 4x^3 - 5/x^2 Easier to differentiate the 2nd term if it isn't written as a fraction so first rewrite y: y = 4x^3 - 5x^(-2) Then differentiate each term by multiplying each term by the current power of...

To write this sum as a single fraction we need to put both of them over a common denominator. Our common denominator will be the simplest thing that has both 3 and 5 as a factor, which is 15 (x-2)/3 + (x+...

Firstly, note the general equation for a quadratic: ax^2+bx+c. We can see that in the above equation, a=1, b=2 and c=-8. When factorising we have to consider the product ac and b. ac=1(-8)=-8 and b=2. Now...

Taking the value at the ordinates f(1) = 13/4, f(2) = 20/4sqrt(2), f(3) = 39/4sqrt(3), f(4) = 9.5 Then the trapezium rule states the integral is approximately 1/2 * [f(1) + 2f(2) + 2f(3) + f(4)], which (u...

x=-1, y=-2 x=2/5, y=11/5 or 2 and 1/5