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Making a substitution for u = 2x^2 Now y = ln(u) dy/dx = du/dx * dy/du du/dx = 4x dy/du = 1/u dy/dx = 4x/u Then substitute 2x^2 back in as u The final answer is 4x/(2x^2) Which can be simplified by divid...

To find the area of a triangle where the length of the base and perpendicular heights are not known, use the sine rule to find the area. This is: Area = 0.5 x a x b x sin(angle between lengths a and b) He...

By calculating the difference between each of the progressions, we see that the first difference is 6, the next is 10, then 14 and finally 18. It is easy to observe that the jump increases by 4 each time,...

Firstly I would draw a diagram of a quadrilateral and label my angles, starting clockwise A,B C and D. Remember that all angles in a quadrilateral add up to 360 degrees. You must use linear equations to s...

Because we know (x+m)^2 expanded will provide x^2+2mx+m^2 and we have the extra addition of a value named n we can strictly focus on ensuring the expansion yields x^2+4x and deal with the -6 value by usin...