The curve C has equation x^2 + 2xy + 3y^2 = 4. Find dy/dx.

Here, we have to use implicit differentiation, along with the product rule. Remember that the product rule is (vu)' = vu'+uv'. Moving through the equation we have: x^2+2xy+3y^2 = 4 ==> 2x +2y + 2x*(dy/dx) + 6y*(dy/dx) = 0, remembering the rules of implicit differentiation. Factorising out dy/dx = -(2x+2y)/(2x+6y).

CB
Answered by Chris B. Maths tutor

12688 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Core 3: Find all the solutions of 2cos(2x) = 1-2sin(x) in the interval 0<x<360


By forming and solving a quadratic equation, solve the equation 5*cosec(x) + cosec^2(x) = 2 - cot^2(x) in the interval 0<x<2*pi, giving the values of x in radians to three significant figures.


find the gradient of the tangent to the curve y=x^2 at the point (4,16)


Use integration by parts to find ∫ (x^2)sin(x) dx. (A good example of having to use the by parts formula twice.)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning