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A gardener uses this formula to work out how much he charges to make a lawn. C = (7(14+A))/3. C is the charge in £, A is the area in m^2. He makes a rectangular lawn measuring 12.5 m by 17.6 m. How much does he charge? [3 marks]

Rectangular Lawn of 12.5 x 17.6m. (Draw Rectangle) Area=LengthHeight A=12.517.6 A=220m^2

Substitute into formula: C=(7(14+A))/3 C=(7(14+220))/3 C=(7(234))/3 C=(1638)/3 C=546

The gar...

Answered by Joshua F. • Maths tutor

4723 Views

Factorise f(x) = 6x^3 -7x^2 -x +2 = 0

Try to find first root: f(1) = 6 - 7 -1 + 2 = 0, therefore x-1 is a root. Find quadratic by inspection: (x-1)( )= 6x^3 -7x^2 -x +2 (x-1)(6x^2 - x - 2) Factorise quadratic: (x-1)(2x+1)(3x-2) = 0

Answered by Tutor40745 D. • Maths tutor

9514 Views

Solve the differential equation dy/dx = y/x(x + 1) , given that when x = 1, y = 1. Your answer should express y explicitly in terms of x.

Rearrange differential equation to get 1/x(x+1) dx = 1/y dy. Separate x side into partial fractions where 1/x(x+1) = 1/x - 1/(x+1). Integrate each side. Resulting equation involves natural logs. Substitut...

Answered by Alexander T. • Maths tutor

16696 Views

The expansion of (1+x)^4 is 1 + 4x +nx^2 + 4x^3 + x^4. Find the value of n. Hence Find the integral of (1+√y)^4 between the values 1 and 0 (one top, zero bottom).

Using Binomial expansion or Pascal's triangle, expand (1+x)^4 to get 1+4x+6x^2+4x^3+x^4. Then, by substituting √y for x, get 1 + 4y^1/2 + 6y +4y^3/2 +y^2. Then, using the rules of integration, the expansi...

Answered by Tutor41123 D. • Maths tutor

6511 Views

Factorise y^2 + 7y + 6

So here we have a quadratic equation because it has the structure a^2 + bx + c. In order to factorise a quadratic we first need to look for two numbers that we can multiply together to get 6 and add toget...

Answered by Victoria H. • Maths tutor

13743 Views