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f(x) = 4x^2 + 8x - 5 ; complete the square to find the turning point of f(x).

4x^2 + 8x - 5 = 0 4(x^2 + 2x - (5/4)) = 0 4((x + 1)^2 - 1^2 - (5/4)) = 0 4((x + 1)^2 - (9/4)) = 0 4(x + 1)^2 - 9 = 0 4(x + 1)^2 - 9 = 0 Turning point is at (-1, -9)

CK
Answered by Charlotte K. Maths tutor
9577 Views

Solve the simultaneous equations: y=x^2+4x-2, y=x+2

Equations: 1). y=x^2+4x-2 2.)y=x+2 x+2=x^2+4x-2 First put equation 1 in equation 2 0=x^2+3x-4 Make one side of the equation equal to 0 0=(x+4)(x-1) Factorise the equations Equations 3).x+4=0 4). x-1=0 One...

PA
Answered by Phoebe A. Maths tutor
3313 Views

(4-2x)/(2x+1)(x+1)(x+3) = A/(2x+1)+B/(x+1)+C(x+3) Find the values of the constants A, B and C

First, multiply throughout by the denominator of the main function to give as follows: 4-2x = A(x+1)(x+3) + B(2x+1)(x+3) + C(2x+1)(x+1) Then, choose values of x which will cause two of the constants to va...

MC
Answered by Michael C. Maths tutor
14318 Views

Solve these simultaneous questions: 2y+x =8 and y-2x = -1.

x = 2 y = 3

CL
Answered by Celine L. Maths tutor
3571 Views

How do you solve the simultaneous equations 3x+y=5 and x-y=3?

The aim of this question is to find x and y by combining these two equations. There are two ways of solving simultaneous equations, elimination and substitution. Elimination can only be used when there ar...

AN
Answered by Andrew N. Maths tutor
6383 Views

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