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Differentiate with respect to x: y=xln(x)

Recall the product rule for differentiation. If y=uv, where u and v are functions defined by functions of x, then we can take the derivative of y as: y'=u'v+v'u () (where ' denotes the derivative) ...

GP
Answered by George P. Maths tutor
6359 Views

Integrate ∫_(-1)^1 3/√(x+2) dx using the substitution u x+2

Step 1:Replace any obvious in the integral with the substitution u=x+2 ∫_(-1)^1 3/√u dx

Step 2: Differentiate the substitution u=x+2 to find an expression for dx (to differentiate multiply by the p...

MY
Answered by Micaela Y. Maths tutor
5472 Views

Show that the integral ∫(1-2 sin^2⁡x)/(1+2sinxcosx) dx = (1/2) ln2 between the limits π/4 and 0. [5 marks]

First, we use the trig identities: cos2x=cos^2x-sin^2x, cos^2x+sin^2x=1 and sin2x=2sinxcosx to transform the integral to ∫(cos2x)/(1+sin2x)dx.
We know that ∫f'(x)/f(x)dx = ln|f(x)|+c, so we let f(x)=...

AC
Answered by Abby C. Maths tutor
15514 Views

Write (√(18)+10)/√(2) in the form: p + q√2 [4 marks]

First, simplify √18 by writing it as √(9x2) = √9 x √2 = 3√2.
Then, rationalise the denominator by multiplying both top and bottom of the fraction by √2.
This gives √2 x √2 = 2 in the denominator...

AC
Answered by Abby C. Maths tutor
20158 Views

f(x) = 4x^2 + 8x - 5 ; complete the square to find the turning point of f(x).

4x^2 + 8x - 5 = 0 4(x^2 + 2x - (5/4)) = 0 4((x + 1)^2 - 1^2 - (5/4)) = 0 4((x + 1)^2 - (9/4)) = 0 4(x + 1)^2 - 9 = 0 4(x + 1)^2 - 9 = 0 Turning point is at (-1, -9)

CK
Answered by Charlotte K. Maths tutor
9384 Views

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