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For the equations 3x + 2y = 4 (1) and 4x + 5y = 17 (2), isolate one of the unknowns in one equation to one side, like so: 3x = 4- 2y. Next multiply the equations so that this unknown is the same in both. ...
When you find the first derivative of the equation and equate it to 0 then solve for x, you will find the x-coordinates of the stationary point(s) of the graph. For example, let's say f(x)=-x3+...
214 ÷ (29)2I would start with the second part of this equation as that looks like it needs simplifying. When 'powers of' are in brackets to each other, they are multipled ...
The general rules are:d(sin x)/ dx = cos xd(cos x)/ dx = -sinxHowever, if you have a constant k in the function such as y = sin(kx), the derivative will be dy/dx = kcos(kx). (For y = cos(kx), the derivati...
y = x^3 - 2x +4/x, dy/dx = 3x^2 - 2 - 4/(x^2) = 0 at the stationary points, 3x^4 - 2x^2 - 4 = 0, substitute in u for x^2: 3u^2 - 2u - 4 = 0, use the quadratic formula: u = (-(-2) +- sqrt((-2)^2 - 4Answered by • Maths tutor3261 Views
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