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subtract one from the other to eliminate y: 3x+y=11; 2x+y=8 --> x=3substitute value of x back in and solve for y: 3(3)+y=11; 9+y=11; --> y=2
(a) Remember: Multiply each term in the left bracket by every term in the right bracket.(x-3)(x+5) = x2+ 5x - 3x -15.Collecting all of the like terms:= x2+ 2x -15.(b) Solve xJWAnswered by Jack W. • Maths tutor10026 Views
The first thing to note about this question is that it's a simultaneous equations question, involving a quadratic. We will have to use substution in order to solve it. So first of all we need to chose whi...
When you differenciate a function, the constant term turns to 0. So a lot of different functions like x2 + 7 and x2 - 3 will have the same derivative, this means that going from the ...
The key to this question is to stay calm and not let yourself be intimidated. You can use the information provided in the question to give you a clear direction to head in- you want to factorise out root ...
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