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To solve for x first divide both sides by 9, giving the equation:(x+3)2 = 4/9Then square root both sides, leading to:x+3 = +/- 2/3Finally subtract 3 from both sides leaving:x = -11/3 or x = -7/...
subtract one from the other to eliminate y: 3x+y=11; 2x+y=8 --> x=3substitute value of x back in and solve for y: 3(3)+y=11; 9+y=11; --> y=2
(a) Remember: Multiply each term in the left bracket by every term in the right bracket.(x-3)(x+5) = x2+ 5x - 3x -15.Collecting all of the like terms:= x2+ 2x -15.(b) Solve xJWAnswered by Jack W. • Maths tutor9626 Views
The first thing to note about this question is that it's a simultaneous equations question, involving a quadratic. We will have to use substution in order to solve it. So first of all we need to chose whi...
When you differenciate a function, the constant term turns to 0. So a lot of different functions like x2 + 7 and x2 - 3 will have the same derivative, this means that going from the ...
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