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x^2 - y = 14, y - 2 = 6x, solve these equations simultaneously

Make y the sbject of the second eqautiom y=6x+2. substitute this for the y in the first equation.the first equation now looks like x2 -(6x+2)=14. Open the brackets and subtract 14 from both si...

JP
Answered by Jai P. Maths tutor
3185 Views

Show that x^2+6x+11 can be written in as (x+p)^2+q, where p and q are integers to be found.

To start, we need to complete the square of the equation. To do this, we divide the coefficient of x by 2. Here, 6/2=3. We then find (x+3)^2, which gives us the first part of the equation we want to expre...

HE
Answered by Hannelore E. Maths tutor
9473 Views

How do you use Substitution to solve simultaneous equations?

For the equations 3x + 2y = 4 (1) and 4x + 5y = 17 (2), isolate one of the unknowns in one equation to one side, like so: 3x = 4- 2y. Next multiply the equations so that this unknown is the same in both. ...

NS
Answered by Niusha S. Maths tutor
3011 Views

How do I find the co-ordinates of a stationary point of a given line and determine whether it is a minimum or a maximum point?

When you find the first derivative of the equation and equate it to 0 then solve for x, you will find the x-coordinates of the stationary point(s) of the graph. For example, let's say f(x)=-x3+...

Answered by Maths tutor
3374 Views

Work out 2^14 ÷ (2^9)^2 in its simplest form

214 ÷ (29)2I would start with the second part of this equation as that looks like it needs simplifying. When 'powers of' are in brackets to each other, they are multipled ...

SD
Answered by Sion D. Maths tutor
6973 Views

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