x^2 = 4(x – 3)^2

This is a quadratic equation, which contains terms up to x2. All quadratic equations can be written in the form ax2 + bx + c = 0 where a, b and c are numbers, and a cannot be equal to zero. Expand the brackets: x2 = 4(x2 - 6x + 9). Multiply RHS brackets by 4: x2 = 4x2 - 24x + 36. Collect x's on one side: 3x2 - 24x + 36 = 0. Simplify: x2 - 8x + 12 = 0. Factorise: (x - 6)(x - 2) = 0. The product of x - 6 and x - 2 is 0, so one or both brackets must also be equal to 0, hence x = 6 or x = 2. Alternatively you can use the quadratic formula provided in the formula sheet and substitute the corresponding numbers in, or solve by completing the square.

JW
Answered by Jennifer W. Maths tutor

4036 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations 1) 3x + 2y = 4 & 2) 4x + 5y = 17


What is the square root of (2^6 + 6^2)


Solve the simultaneous equations 3x + y = 11 and 2x + y = 8.


Increase 32 million by 4%. Give your answer correct to the nearest million.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning