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1/2 *e^(x)(sin x -cos x)
Use integration by parts to obtain:u=arcsin(x), u'=1/(1-x2)0.5, and v'=1, v=xUsing the equation: integral of uv' = uv - integral of u'vintegral of arcsin(x) = xarcsin(x) - inte...
72 / (3+4+5) = 6base :36 = 18height :46 = 24area = (base * height) /2area = (18*24)/2=216 cm ^2
x2+6x+5=0 First of all half the x coefficient and write (x+6/2)2 the take away the (6/2)2 and add on the 5 (x+3)2-9+5=0(x+3)2-4=0 ...
y=5x2-2x+3 Differentiate to find the equation of the gradient of the curvedy/dx=10x-2 Substitute x=0 to find the gradient at the point x=0dy/dx=-2y=50^2-2Answered by • Maths tutor5271 Views
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