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Expand the following (x+4)(x+2)

The most important thing to remember when expanding brackets is to make sure that all terms in the one brackets have been multiplied with all the terms in the other.In this case we have two terms in each ...

JG
Answered by James G. Maths tutor
3072 Views

Differentiate 2e^(3x^2+6x)

Subsitute in u = 3x^2 + 6x and use chain rule to get dy/dx = dx/du x dy/dx to get dy/dx = 2(6x+6)e^(3x^2 +6)

NC
Answered by Nasser C. Maths tutor
3831 Views

Given that the binomial expansion of (1+kx)^n begins 1+8x+16x^2+... a) find k and n b) for what x is this expansion valid?

a) We compare the expansion given to the standard binomial expansion (remembering the powers of k).(1+kx)n=1+n(kx)+(n(n-1)/2)(kx)2+...As this is true for all x (for which the expansi...

GC
Answered by George C. Maths tutor
4985 Views

Given that y=(sin4x)(sec3x), use the product rule to find dy/dx

First, recall the Product rule: f(x)=g(x)*h(x), f'(x)=h(x)*g'(x)+h'(x)*g(x)This reveals the next step, to find the derivatives of our two subsidiary functions(g and h) d/dx * (sin4x) = 4cos(4x) , and d/dx...

EF
Answered by Edward F. Maths tutor
3871 Views

A box contains 7 caramel doughnuts. They have masses of 56 g, 67 g, 45 g, 56 g, 58 g, 49 g and 50 g. Find the median, mean and mode values of these masses. Bonus: What mass of doughnut could be added to the box to make the mean mass = 61 g.

Median: Order the values from lowest to highest: 45, 49, 50, 56, 56, 58, 67. Pick the middle value. Answer = 56 g.Mode: The most common value. Answer = 56 g.Mean: Add all the values up, then divide the re...

KG
Answered by Kate G. Maths tutor
2455 Views

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