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Find the gradient of the tangent to the curve y=4x^2 - 7x at x = 2

First, we differentiate our equation using the power rule:dy/dx = 8x - 7This is the gradient of our tangent, to the original equation, at any point x. So, to calculate the gradient at x = 2, we substitute...

Answered by Luke A. • Maths tutor

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a typical question would be a setof parametric equations y(t) and x(t), asking you to find dy/dx and then the tangent/normal to the curve at a certain point (ie t = 2)

this question is a great example as we have many different aspects of a level maths workng together into one.initialy you will use use chain rule to find dy/dx = dy/du * du/dx.then you will either keep th...

Answered by Thomas S. • Maths tutor

2912 Views

Solve algebraically the simultaneous equations: x^2 + y^2 = 25 and y - 3x = 13

Firstly, we need to use one equation to find an expression for one variable in terms of the other. Then we can substitute this expression into the other equation and solve for that variable. Using this nu...

Answered by Gregor W. • Maths tutor

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Having studied Spanish before I know what will help achieve the top grades.I can help with speaking practice and help develop your accent to sound more fluent and natural in your Spanish.I know about many...

Answered by Lucy C. • Maths tutor

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Solve the two simultaneous equations. 1. x^2 + y^2 = 25, 2. y - 3x = 13

The way to solve simultaneous equations is to 'slot in' one equation into the other. For this question, we will use the information in equation 2 (after manipulating it) to solve equation one. First, we a...

Answered by Jazir L. • Maths tutor

3292 Views