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Let's think backwards - what can we multiply to get this result?First, let's take a simpler example, an expression:(x-1)(x-2). We multiply 1st term of the 1st brackets by terms of the 2nd bracket and then...
f(x) = x3 + 3x V = π ∫ (f(x)2) dx V = π ∫02 (x3 + 3x)(x3 + 3x) dx V = π ∫02 (x6 + 6x4ZCAnswered by Zac C. • Maths tutor3121 Views
Mary = 20km/h Jason = 15km/h s = d/t After 1.5 hours, Mary = 30km and Jason = 22.5km 30 + 22.5 = 52.5km
Factorising gives: y = (x+2)(x+1) = 0. y only equals 0 when (x+2)=0 or (x+1)=0. Therefore x=-2 or x=-1
Differentiate wrt x. This leaves dy/dx = 3x^2 + 6x and equate this to 0 as we are looking for stationary points.So, 3x^2 + 6x = 0. Factorise to get x(3x +6) = 0. So x = 0 and x = -2 are the two solutions....
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