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f(x) = x^3 + 3x^2 + 5. Find (a) f ′′(x), (b) ∫f(x)dx.

(a) To find the second derivative of f(x) we must differentiate f twice.the first derivative of f is f'(x)= 3x^2 + 6xthe second derivative therefore is f''(x)= 6x +6
(b) The integral of f(x) with res...

SC
Answered by Samraj C. Maths tutor
7387 Views

How would you solve 4x > 7 - 10x ?

When solving an inequality, you want to get all of the x terms on one side, just like when you're solving an equation. Therefore, adding 10x to each side would give us:4x (+10x) > 7 - 10x (+10x) which ...

SG
Answered by Sarah G. Maths tutor
3020 Views

Solve, giving your answer to 3 s.f. : 2^(2x) - 6(2^(x) ) + 5 = 0

22x - 6(2x ) + 5 = 0let y = 2xy2 - 6y + 5 = 0(y-5)(y-1) = 0 y=5, y=12x = 5, therefore, x = log25 = 2.32 (3 s.f.)2x = 1, therefo...

JO
Answered by Jess O. Maths tutor
4204 Views

Find the gradient of the function f(x,y)=x^3 + y^3 -3xy at the point (2,1), given that f(2,1) = 6.

Firstly, establish that the correct method to do this is via differentiation: specifically implicit differentiation. To find the gradient, we need to find dy/dx. The differential with res...

DD
Answered by Daniel D. Maths tutor
5350 Views

If f(x) = sin(2x)/(x^2) find f'(x)

As f(x) is in the form of u(x)/v(x) we can apply the rule that f'(x) = (u'(x)*v(x) - v'(x)*u(x))/(v(x)2), pulled from the C3 formula booklet.
If u(x) = sin(2x) then u'(x) = 2cos(2x).
...

LR
Answered by Leo R. Maths tutor
3334 Views

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