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step 1 ; expand the brackets5x - 15 = 4y - 3xystep 2 ; group together x values on one side5x + 3xy = 4y + 15step 3 ; single out xx (5+3y) = 4y +15step 4 ; make x the subjectx = (4y + 15) / (5+3y)

Using Pythagoras' theorem: a² = b² + c²You can use the length of the other two sides to calculate a.

When solving simultaneous equations the first step is to take one of the equations and rearrange it to make one of the terms the subject. In this case lets take the equation 1+y=2x. Take the 1 over to the...

First rearrange the equation so the LHS is equal to Zero:X²-13x-30=0Then find the factors of -30:-1,30/1,-30-2,15/2,-15-3,10/3,-10-6,5/6,-5Chose the factor pairs which add to equal -13which is ...

To solve this first we need to simplify the equation by multiplying the denominators by a common factor. If we multiply both sides of the equation by 6 we shall get an equation that is expressed with deno...