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Differentiate the following: y=sin(x^2+2)

dy/dx = 2xcos(x²+2)

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make x the subject of 5(x-3) = y(4-3x)

step 1 ; expand the brackets5x - 15 = 4y - 3xystep 2 ; group together x values on one side5x + 3xy = 4y + 15step 3 ; single out xx (5+3y) = 4y +15step 4 ; make x the subjectx = (4y + 15) / (5+3y)

Answered by Sofia A. • Maths tutor

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Write down the length of side "a"

Using Pythagoras' theorem: a² = b² + c²You can use the length of the other two sides to calculate a.

Answered by Rhys K. • Maths tutor

2799 Views

Solve these simultaneous equations 2y+x=8, 1+y=2x.

When solving simultaneous equations the first step is to take one of the equations and rearrange it to make one of the terms the subject. In this case lets take the equation 1+y=2x. Take the 1 over to the...

Answered by Lewis K. • Maths tutor

3542 Views

Find the value of roots of the quadratic: x^2-13x=30

First rearrange the equation so the LHS is equal to Zero:X²-13x-30=0Then find the factors of -30:-1,30/1,-30-2,15/2,-15-3,10/3,-10-6,5/6,-5Chose the factor pairs which add to equal -13which is ...

Answered by Tabonga Z. • Maths tutor

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