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We will call sandwiches S and packets of crisps C. These are the 'unknowns'. From the information we can write down two equations. Equation 1: 3S + 2C = 9 and Equation 2: 5S + 6C = 19. We need two equatio...

Firstly, factorise.
(2x + 9) (x - 3) = 0
2x + 9 =0 x-3 = 02x = -9 x = 3 x = -9/2

If d is directly proportional to the square of t, we write this as d= kt² , where k = the proportionality constant which we must find. Substitute in the values given in the question into our e...

A parametric equation is where both x and y are expressed separately, in terms of a parameter (t). In order to differentiate them we must use the chain rule, which here would be dy/dx= dy/dt ÷ dx/dt. The ...

First we take the derivative of the function, this gives us dy/dx = cos(x)
Now we work out the different x values for y = 0 and y = 1.
sin(x) = 0 => x = 0, sin(x) = 1 => x = pi/2 (90 degre...