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(a) We can ‘get rid of’ a square root in the denominator simply by multiplying by 1 (value of the fraction stays unchanged) in a suitable form. We will take advantage of this formula: (a+b)(a-b)=a^2...
The starting point for a question like this is to differentiate the function - in this case the curve y=3x2 -7x+5 . We calculate that dy/dx=6x-7 . The question tells us that we are interested i...
Logically work through the problem: 1) Plot all the information that is available so you can visualise the problem better (always encouraged for graphical questions) 2) Understand that the gradient of the...
f'(x) = 3λx^2f''(x) = 6λxFor the inflection point (x0,y0), it is true that f''(x0)=0 so 6λxo=0 => x0= 0 (since λ cannot be zero)Therefore, the inf...
cos(2x)=cos2(x)-sin2(x)=2cos2(x)-1Therefore:cos(2x)/cos2(x)=(2cos2(x)-1)/cos2(x)=2cos2(x)/cos2(x) - 1/cosHFAnswered by Hugo F. • Maths tutor6424 Views
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