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Express 4x/(x^2-9) - 2/(x+3) as a single fraction in its simplest form.

To satisfy the condition of substracting two fractions with unlike denominators, a common denominator needs to be found. By recognizing x^2 - 9 = (x-3)(x+3), we can rewrite the question as 4x/(x-3)(x+3) -...

YC
Answered by Ye C. Maths tutor
5921 Views

Show that r^2(r + 1)^2 - r^2(r - 1)^2 ≡ 4r^3.

Start with the left hand side (LHS) of the equation. r^2(r + 1)^2 - r^2(r - 1)^2Take the equivalent terms from the separate parts of the LHS outside of set of brackets.r^2[(r + 1)^2 - (r - 1)^2]Expand t...

AD
Answered by Andrew D. Maths tutor
6896 Views

Solve the simultaneous equations 8x+2y=34 and 4x+2y=18

1.Simplify the two equations: 4x+y=17and 2x+y=9. 2. Rearrange one of the equations to make y=: y=9-2x. 3.Substitute into other equation:4x+9-2x=17. 4. Simplify:2x=8 x=4. 5.Substitute back into either of t...

LM
Answered by Lara M. Maths tutor
3502 Views

Two particles, A and B, are moving directly towards each other on a straight line with speeds of 6 m/s and 8 m/s respectively. The mass of A is 3 kg, and the mass of B is 2 kg. They collide to form a single particle of speed "v" m/s. Find v.

The student should apply their knowledge of conservation of momentum. Also, I would always encourage the student to draw a diagram for all mechanics questions as it helps visualise the problem.total chang...

KH
Answered by Kieran H. Maths tutor
4327 Views

Solve the quadratic: 3x^2+4x = 20 to find x.

Quadratic formula: where ax^2+bx+c =0, x = (-b±√(b^2-4ac))/2a.Rearrange the formula in the question to get 3x^2+4x-20 = 0.From the quadratic in the question we can see that a = 3, b = 4, c = -20.Therefore...

SF
Answered by Samuel F. Maths tutor
5396 Views

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