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This question is done by substituting either the x or y. To do this, rearrange the second equation to make y the subject. We make y the subject as it keeps the equation and calculation simple. After rearr...

I would tell them to start multiplying out the first brackets (x+2)(x+3)! I would do this by timesing x by everything in the second bracket and then 2 by everything in the second brakcet! Giving the answe...

This can't be differentiated with the usual methods (chain rule, product rule). First we set y = x^x, and our objective is to calculate dy/dx in terms of x.
To turn this function into more ...

This is a modulus question, asking us to solve for x. As there are two variables in this equation, it is impossible for us to solve for an actual number, so we are asked to answer in terms of a. The easie...

Partial fractions is a method of expressing a single fraction with multiple factors in the denominator as a sum of fractions. First we must factorise the denominator (bottom of the fraction).x²...