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x = -3 , x= -7
x = 1, y = 2
If the second derivative of an equation is positive (d2y /dx2 > 0), we can see that this point on a curve is a minimum. This is because, where the first derivative finds the grad...
For integration by parts, the integral is uv - ∫ u' v dx. First we take u = ln x and v' = 1. While we could have u and v' be the opposite at this stage, it becomes apparent later on that we can't do this ...
First Differentiate the equation to getdy/dx=6x+2Equal this to 0 to find the stationary pointdy/dx=0=6x+2 => 6x=-2=> x=-2/6=> x=-1/3differentiate again to find the whether it is a maximum o...
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