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Firstly, show the equation is true for n = 3 (as this is the samllest n that nC3 is defined): LHS = (2C2) = 1 = (3C3) = RHStherefore, true for n=3.Then assume true for n = k:(2C2)+(3C2)+(4C2)+...+(k...
log10[(1/2√2)(p+2q)]=(1/2)(log10p+log10q)log10[(1/2√2)(p+2q)]=(1/2)(log10pq)log10[(1/2√2)(p+2q)]=log10(pq)1/2...
The first thing to notice here is that the denominator of the integrand is a case of 'difference of two squares'. The integral, which I will call I, can be rewritten as the integral of 4/((1+x)(1-x)) dx. ...
Firstly we remind ourselves of the integration by parts formula. The formula used to integrate u dv/dx with respect to x = uv - the integral of v du/dx with respect to x.So the first thing we have t...
4/(x-3)*(x+2)/x= 4x+8/ x2 -3xsub in a for x4a+8/a2-3athen equate to 1: 4a+8/a2-3a=1Times the bottom half of the equation up4a+8=a2-3aThe move the 4a+8 acr...
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