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tan(3x)=tan(2x+x), by using the identity for tan(A+B)=(tan(A)+tan(B))/(1-tan(A)tan(B)),tan(3x)=tan(2x+x)=(tan(2x)+tan(x))/(1-tan(2x)tan(x)), using it again for tan(2x),tan(3x)=tan(2x+x)=([(tan(x)+tan(x))/...

Seeing as this is arguably an essay or short essay topic the answer given below will be a brief summation of what a student may want to include in their answers in regards to this specific text as well as...

When solving simultaneous equations, there are two methods: substitution and elimination. For this question, as one of the equations is a quadratic, the substitution method has to be used. The second equa...

common factor is 6x therefore it is 6x(x-2)

rearrange gives z = [(1+2i)^2]/(2+i)expanding (1+2i)^2 gives 4i-3 therefore this becomes (4i-3)/2+i multiply that by the conjugate (2-i)/(2-i) to give (11i-2)/5therefore z= -2/5 + 11i/5