Differentiate the equation y = (1+x^2)^3 with respect to (w.r.t.) x using the chain rule. (Find dy/dx)

For this example it would be better to use a dummy variable (a variable just to help with solving the equation but isn't a part of the final answer). Let us say our dummy variable, t = 1+x^2. So, substituting t into the equation, we now have y = t^3. Let us differentiate y w.r.t. t, dy/dt = 3t^2 and let us differentiate t w.r.t. x, dt/dx = 2x. So now, we have two new equations, dy/dt and dt/dx. If we multiply these two together using the chain rule - dy/dt * dt/dx = dy/dx (which is what we are trying to find), we end up with dy/dx = 3t^2 * 2x. Substitute x back into the equation dy/dx = 3(1+x^2)^2 * 2x = 6x(1+x^2)^2. (FINAL ANSWER)

Answered by Paolo A. Maths tutor

5177 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Supposing y = arcsin(x), find dy/dx


find the integral of (2x - (3x^1/2) +1) between 9 and 4


A mass of 3kg rests on a rough plane inclined at 60 degrees to the horizontal. The coefficient of friction is 1/5. Find the force P acting parallel to the plane applied to the mass, in order to just prevent motion down the plane.


Find the equation of the tangent to the curve y = 2x^2 + x - 1 at the point where x = 1.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy