Solve for x, 5sin(x) - 3cos(x) = 2 , in the interval 0<x<2pi

5sin(x)-3cos(x)=2

Express in the form Rsin(x-@) = Rsin(x)cos@ - Rcos(x)sin@

Rcos@ =5

Rsin@ = 3    

tan@ = 3/5           @=tan-1(3/5)= 0.540

R = sqrt(52 +32 )= sqrt(34)

sqrt(34)sin(x-0.540) = 2

sin(x - 0.540) = 0.343

Let Y = x-0.540

sinY = 0.343         in the interval -0.540 < Y < 5.743

Y = sin-1 (0.343)=0.350

Using CAST diagrams, we obtain 0.350 and pi-0.350 in this interval

Y = 0.350, 2.791

x = 0.350 + 0.540, 2.791 + 0.540

x = 0.890, 3.331

Answered by Stefan M. Maths tutor

3172 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How to calculate the inverse of a 2x2 matrix


An 1kg ball collides normally with a fixed vertical wall. Its incoming speed is 8 m/s and its speed after the collision is 4 m/s . Calculate the change in momentum of the particle. If the collision lasts 0.5 s calculate the impact force.


ln(2x^2 + 9x – 5) = 1 + ln(x^2 + 2x – 15). Express x in terms of e


Express (3 - sqrt(5))^2 in the form m + n*sqrt(5), where m and n are integers.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy