Find the first 4 term of the binomial expansion (2-4x)^5

Step 1: Look at formula in formula booklet provided and write out formula.

Formula: (a+b)ⁿ= aⁿ+ ⁿc₁a^n-1b + ⁿC₂a^n-1b²+...+ⁿC_ra^n-rb^r 

In this question our a=2 our b=-4x and our n=5

Therefore our first 4 terms are:

4⁵ + 52⁴(-4x) + 102³(-4x)² + 102²(-4x)³

= 32 - 320x +1280x² -2560x³