Find the first 4 term of the binomial expansion (2-4x)^5

Step 1: Look at formula in formula booklet provided and write out formula.

Formula: (a+b)n= annc1an-1b + nC2an-1b2+...+nCran-rb

In this question our a=2 our b=-4x and our n=5

Therefore our first 4 terms are:

4+ 524(-4x) + 1023(-4x)2 + 1022(-4x)3

= 32 - 320x +1280x2 -2560x3

CR

Related Maths A Level answers

All answers ▸

solve the differential equation dy/dx=(3x*exp(4y))/(7+(2x^(2))^(2) when y = 0, x = 2


How do you prove that (3^n)-1 is always a multiple of 2?


f(x) = sinx. Using differentiation from first principles find the exact value of f' (π/6).


What is 'grouping' and how does it work?