Find the first 4 term of the binomial expansion (2-4x)^5
Step 1: Look at formula in formula booklet provided and write out formula.
Formula: (a+b)n= an+ nc1an-1b + nC2an-1b2+...+nCran-rbr
In this question our a=2 our b=-4x and our n=5
Therefore our first 4 terms are:
45 + 524(-4x) + 1023(-4x)2 + 1022(-4x)3
= 32 - 320x +1280x2 -2560x3
CR
Related Maths A Level answers
All answers ▸For which values of k does the quadratic equation 2x^2+kx+3=0 only have one unique solution?
Express x^2-4x+9 in the form (x-p)^2+q where p and q are integers
The curve C has equation 4x^2 – y^3 – 4xy + 2^y = 0 The point P with coordinates (–2, 4) lies on C . Find the exact value of dy/dx at the point P .
Find f(x^(1/2)+4)dx (Where f is the integral sign)