A 6.0W bulb is connected to a source of 480J of energy. Assuming the system is 100% efficient, and the bulb runs at full power, how long can it stay lit?

  • Bulb power = 6.0W - Energy provided = 480J - Use equation P = E / t (Power = energy/time) where power is in watts, energy is in joules, and time is in seconds - Rearrange the equation to give t = E / P (time = energy/power) to find the time in seconds - Plug in the values to give t = 480/6 = 80 - Therefore time = 80 seconds.
LW
Answered by Lily W. Physics tutor

4003 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

How is a PET scanner able to locate a tumour in the patient's body?


The charge that flows through the shower in 300 seconds is 18000C. The electric shower has a power of 13.8 kW. Calculate the resistance of the heating element in the shower.


Is momentum a vector quantity? Why?


If v = 10, a = 2 and t = 4, what is u


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning