Calculate the amount (in moles) of iron 3 nitrate in a 2.16g sample.

Formula of Iron 3 Nitrate is Fe(NO3)3. Moles = mass/Mr.

Already given mass = 2.16g

Want to work out amount in moles.

Need to calculate Mr of Iron 3 nitrate, put into equation with mass -> find moles.

Using periodic table Mr is always the bottom number (mass of an atom relative to carbon which is always taken as 12)

Mr of iron (Fe) is 56

Mr of oxygen (O) is 16

Mr of nitrogen (N) is 14

In the formula Fe(NO3)3 there are: 

1 molecule of iron -> 1 x 56 = 56

3 molecules of nitrogen (due to 3 outside the bracket) -> 3 x 14 = 42

3 (inside bracket) x 3 (outside bracket) = 9 molecules of oxygen. 9 x 16 = 144

56 + 42 + 144 = Mr of Iron 3 nitrate = 242

As above, moles = mass/mr

So moles of iron 3 nitrate = 2.16/242 = 8.93x10-3

KW
Answered by Katherine W. Chemistry tutor

7807 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Name and explain briefly the main stages of mass spectroscopy.


Explain why Magnesium has a greater second ionisation energy than strontium


3.786g of hydrated zinc sulphate, ZnSO4•xH2O, is heated to remove all water of crystallisation. The mass of anhydrous ZnSO4 formed is 2.122g. What is the formula of the hydrated zinc sulphate?


Can you explain acylation?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning