The mass of a substance is increasing exponentially. Initially its mass is 37.5g, 5 months later its mass is 52g. What is its mass 9 months after the initial value to 2 d.p?

M=37.5ekt 52=37.5ek5 52/37.5=e5k ln(52/37.5)=5k (1/5)(ln(52/37.5))=k k≈0.06538 when t=9, M=37.5e9*0.06538 M=67.54

RR
Answered by Riccardo R. Maths tutor

4075 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Calculate the indefinite integral of ln(x)?


Integrate sinxcosx dx


Given that y > 0, find ∫((3y - 4)/y(3y + 2)) dy (taken from the Edexcel C4 2016 paper)


How do you integrate a fraction when x is on the numerator and denominator?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences