Find the value of dy/dx at the point where x = 2 on the curve with equation y = x^ 2 √(5x – 1).

Here we must use the product rule to differeniate because x appears in both terms of the equation, therefore both parts must be differentiated. So we will set u= xand v= (5x-1)^(1/2) written like this makes the power easy to see. du/dx=2x dv/dx=(1/2)(5)(5x-1)^(-1/2) Product rule dy/dx = udv/dx + vdu/dx dy/dx = (5/2)x2(5x-1)^(-1/2) + 2x(5x-1)^(1/2) Sub in the value of 2 dy/dx = (5/2)22(5(2)-1)^(-1/2) + 2(2)(5(2)-1)^(1/2) dy/dx = 46/3 = 20/21/3 + 12 12 can be written as 36/3 so dy/dx= 10/3 + 36/3 = 46/3 

LT
Answered by Lucy T. Maths tutor

12348 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How would you solve (2x+16)/(x+6)(x+7) in partial fractions?


Find the stationary points of y = 4(x^2 - 4)^3


How would I go about drawing the graph of f(x) = sin(x)/(e^x) for -π≤x≤2π?


Differentiate 5x^3 + 4x^2 + 5x + 9


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning