A curve C is defined by the equation sin3y + 3y*e^(-2x) + 2x^2 = 5, find dy/dx

d(sin3y)/dx= 3cos3y*(dy/dx)d(3ye^(-2x))/dx = -6ye^(-2x) + 3(dy/dx)e^(-2x)d(2x^2)/dx = 4xd(5)/dx = 0so3cos3y(dy/dx) - 6y*e^(-2x) + 3(dy/dx)e^(-2x) + 4x = 0rearrange the equationdy/dx = (6ye^(-2x)-4x)/(3cos3y + 3e^(-2x))

ZZ
Answered by Zhaohui Z. Maths tutor

5456 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Derive the quadratic equation.


find the integral of ((3x-2)/(6x^2-8x+3)) with respect to x between x=2 and x=1. (hint use substitution u=denominator)


Find the equation of the tangent to the curve y = 2 ln(2e - x) at the point on the curve where x = e.


Differentiate xcos(x) with respect to x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning