Complete the square of 2x^2+16x-24 and hence state the minimum value of the function
2[(x^2+8x-12) [Explain basic complete the square technique]2[(x+4)^2 -16 -12]2[(x+4)^2-28]2(x+4)^2-56The term (x+4)^2 is always greater or equal to 0. So the smallest value it can have is 0. So the minimum value of the function will be -56. (Draw a sketch of the curve )
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