Solve the simultaneous equations : x^2 + y^2 = 13 and x = y - 5 .

Below is the solution to the aforementioned question. In order to solve a simultaneous equation, one has to write one of the unkown variables in terms of the other. In this case, x was already written in relation to y, which means we can replace x in the first equation with y - 5. This allows us to have an equation with only one unkown variable, y. We solve this equation and we end up with two possible solutions for y. We find out x in both those solutions and we have our answers. Below is the mathematical solution as well. x2+ y2 = 13 x = y - 5 (y - 5)2 + y2 = 13 (y - 5)(y - 5) + y2 = 13 y2-5y - 5y + 25 + y2 = 13 2y2-10y + 25 = 13 2y2-10y + 12 = 0 y2-5y + 6 = 0 (y - 3)(y - 2) = 0 y1= 3 and y2 = 2 x1 = (3) - 5 and x2 = (2) - 5 x1 = -2 and x2 = -3

SG
Answered by Sebastian G. Maths tutor

16408 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you solve simultaneous equtions?


Hannah's sweet problem (Edexcel 2015): There are n sweets, 6 are orange, rest of the sweets are yellow. She takes 2 sweets randomly without replacing them and the probability that 2 orange sweets are chosen is 1/3. Show that n^2-n-90 = 0.


How do you solve an equation like: 5/(x+2) + 3/(x-3) = 2?


Solve the following equation: 7x + 6 = -5x - 42


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning