How to determine the modulus of a complex number?

All complex numbers are in the form a+bi where a is the real part of the complex number and b is the imaginary part. Therefore if we are plotting the complex number on argand diagram the value of a tells us where the real part lies (i.e the x value) and the value of b tells us where the imaginary part is (i.e the y value).

The modulus is the distance from the origin to this point, so can be found using pythagorus' theorem. Therefore if z is the modulus z^2=a^2+b^2. We can see this method will work wherever the point is on the argand diagram and so know that sqrt(a^2+b^2) will always give us the modulus of a complex number. 

 

LH
Answered by Luke H. Further Mathematics tutor

10185 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Prove by induction that for all positive integers n , f(n) = 2^(3n+1) + 3*5^(2n+1) , is divisible by 17.


It is given that f(x)=(x^2 +9x)/((x-1)(x^2 +9)). (i) Express f(x) in partial fractions. (ii) Hence find the integral of f(x) with respect to x.


Find the general solution of: y'' + 4y' + 13y = sin(x)


Find the inverse of the general 2x2 matrix A= ([a, b],[c, d]) when does this inverse exist?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning