The curve C has equation y = 3x^4 – 8x^3 – 3. Find dy/dx.

To find dy/dx, the differential, of any function... you must times the coefficient of each variable of x by its power, then reduce the power by one. Using this information we can work out that 3x^4 turns to 12x^3, and -8x^3 turns to -24x^2. Since -3 doesn't appear to be a coefficient of x, we must imagine it to be -3x^0. Therefore when you multiple the coefficient, 3, by 0, this part of the equation turns to zero.
Therefore if curve C has equation y = 3x^4 – 8x^3 – 3. We know that dy/dx = 12x^3 - 24x^2 (+0).

JC

Related Maths A Level answers

All answers ▸

A curve has equation y = f(x) and passes through the point (4, 22). Given that f'(x) = 3x^2 - 3x^(1/2) - 7, use integration to find f(x), giving each term in its simplest form


Express 4sinx-cos(pi/2 - x) as a single trignometric function


Integrate ln(x) by parts then differentiate to prove the result is correct


A circle has eqn x^2 + y^2 + 2x - 6y - 40 = 0. Rewrite in the form (x-a)^2 + (y-b)^2 = d.