Find the stationary points of the function z = 3x(x+y)3 - x3 + 24x

z = 3x(x+y)3 - x3 + 24xDifferentiating partially with respect to x and with respect to y:∂z/∂x = 3(x+y)3 + 9x(x+y)2 - 3x2 + 24∂z/∂y = 9x(x+y)2At stationary points: ∂z/∂x = 0 and ∂z/∂y = 0.From ∂z/∂y = 0 we deduce: x = 0 or y = -x.We consider ∂z/∂x = 0 in each of these cases:For x = 0:3y3 + 24 = 0y = -2Hence a stationary point at (0, -2, 0)For y = -x:-3x2 + 24 = 0x = 2√2 and x = -2√2Hence stationary points at (2√2, -2√2, 32√2) and (-2√2, 2√2, -32√2)

HT
Answered by Harvey T. Further Mathematics tutor

2470 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

(FP1) Given k = q + 3i and z = w^2 - 8w* - 18q^2 i, and if w is purely imaginary, show that there is only one possible non-zero value of z


Why is the argument of a+bi equal to arctan(b/a)?


When using the method of partial fractions how do you choose what type of numerator to use and how do you know how many partial fractions there are?


Solve the second order differential equation d^2y/dx^2 - 4dy/dx + 5y = 15cos(x), given that when x = 0, y = 1 and when x = 0, dy/dx = 0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning