Find both stationary points for y= 4x^(3)-3x^(2)-60x+24. Also find the nature of those points.
y= 4x3- 3x2- 60x+ 24dy/dx = 12x2- 6x- 60 = 2x2- x- 10 = (2x-5)(x+2)
So stationary points are at x= 5/2 and x= -2
d2x/dy2 = 24x - 6
24(5/2) - 6 = positive so this is a minimum point
24(-2) - 6 = negative so this is a maximum point
WM
Related Maths A Level answers
All answers ▸Find dy/dx if y=(x^3)(e^2x)
The curve C has the equation: y=3x^2*(x+2)^6 Find dy/dx
A curve is defined by the parametric equations x=t^2/2 +1, y=4/t -1. Find the gradient of the curve when t =2.
x is an angle, if 180 > x > 90 and sinx = √2 / 4 what is the value of angle x