A curve has equation y = ax^2 + 3x, when x= -1, the gradient of the curve is -5. Work out the value of a.

The gradient of a curve at a point is given by dy/dxDifferentiate the equationplug in the valuesdy/dx = 2ax + 3x = -1, dy/dx = -5-5 = 2a*-1 + 38 = 2aa = 4

SE
Answered by Salma E. Further Mathematics tutor

6133 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

If z=4+i, what is 1/z? (in the form a+bi)


Solve the simultaneous equations xy=2 and y=3x+5.


A=(1,a;0,1/2) B=(1,-1;0,2) AB=I, calculate the value of a.


How do I find the limit as x-->infinity of (4x^2+5)/(x^2-6)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning