A=(1,a;0,1/2) B=(1,-1;0,2) AB=I, calculate the value of a.

First notice I is the 2x2 identity matrix (1,0;0,1) now we can form an equation to solve for a, look for an entry where a is involved the (1,2) entry of I is 0 and calculated by 1(-1)+2a=0 now solving gives a=1/2

DS
Answered by Dylan S. Further Mathematics tutor

2383 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

The coefficient of the x^3 term in the expansion of (3x + a)^4 is 216. Find the value of a.


Find the tangent to the equation y=x^2 -2x +4 when x=2


The equation of a curve is y = x^2 - 5x. Work out dy/dx


How do I find the limit as x-->infinity of (4x^2+5)/(x^2-6)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning