Solve simultaneously 2x+3y=8, 3x+2y=7 to calculate values of x and y.

First of all, we must multiply each equation by a suitable number in order to get the same leading coefficient. In simple terms, we must make the coefficient of the x or the y in both equations the same. So here it is easy to multiply the first equation by 3 to get 6x+9y=24 and the second by 2 which gives us 6x+4y=14. Now if we subtract equation 1 by equation 2, we have 5y=10. To make y the subject, we must divide both sides by 5 which gives us y=2.Let us substitute this value of y into 2x+3y=8. We have 2x+(3*2)=8. Again if we rearrange this for x, we have x=1.

VL

Related Maths GCSE answers

All answers ▸

Show that the lines y-5x=2 and 6y-30x=36 are parallel


Show that the function f(x) = x^2 + 2x + 2 is always positive for real values of x


A book was reduced by 35% in a sale. It's new price is £16. What was the original price ?


Solve the simultaneous equations 5x + y = 21 and x - 3y = 9