Solve simultaneously 2x+3y=8, 3x+2y=7 to calculate values of x and y.

First of all, we must multiply each equation by a suitable number in order to get the same leading coefficient. In simple terms, we must make the coefficient of the x or the y in both equations the same. So here it is easy to multiply the first equation by 3 to get 6x+9y=24 and the second by 2 which gives us 6x+4y=14. Now if we subtract equation 1 by equation 2, we have 5y=10. To make y the subject, we must divide both sides by 5 which gives us y=2.Let us substitute this value of y into 2x+3y=8. We have 2x+(3*2)=8. Again if we rearrange this for x, we have x=1.

VL
Answered by Vasant L. Maths tutor

6852 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There are 11 pens in a box, 8 are black, 3 are red. Two pens are taken out at random without replacement. What is the probability the pens are the same colour?


Differentiate (2a+3)^5/2 with respect to a


solve the simultaneous equations x^2 + y^2 = 5 and 3x+1=y


How do I expand (3x + 6)(x + 2) ?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning