Solve simultaneously 2x+3y=8, 3x+2y=7 to calculate values of x and y.

First of all, we must multiply each equation by a suitable number in order to get the same leading coefficient. In simple terms, we must make the coefficient of the x or the y in both equations the same. So here it is easy to multiply the first equation by 3 to get 6x+9y=24 and the second by 2 which gives us 6x+4y=14. Now if we subtract equation 1 by equation 2, we have 5y=10. To make y the subject, we must divide both sides by 5 which gives us y=2.Let us substitute this value of y into 2x+3y=8. We have 2x+(3*2)=8. Again if we rearrange this for x, we have x=1.

VL
Answered by Vasant L. Maths tutor

5648 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Write 0.319319... as a fraction in its lowest terms


Factorise and solve x^2 - 8x + 15 = 0.


Show x^2 + 8x +15 = 0 in the form of (x+b)^2 +c (complete the square) and then solve the equation


Find the derivative y= x^2-6x+20?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences